Water · Worked step by step

How many gallons are in 800 feet of 12 inch main?

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The problem

A water main is 12 inches across and 800 feet long. How many gallons does it hold when full?

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3 steps

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Every step gets a plain-words explanation here, so you always know exactly what just happened and why.

The written version, step by step

  1. 1

    Change inches to feet

    across = 12 in = 1 ft

    • 12 inches divided by 12 is 1 foot.
    • So the main is 1 foot across.
    • That makes the circle simple.
  2. 2

    Find the circle end

    area = 0.785 × 1 × 1 • area = 0.785 sq ft

    • Circle end is 0.785 times across times across.
    • 1 times 1 is 1.
    • So the area is just 0.785 square feet.

    Quick trick: Anything times 1 stays the same, so a 1-foot pipe end is exactly 0.785.

  3. 3

    Times length, then gallons

    cubic feet = 0.785 × 800 = 628 • gallons = 628 × 7.48 = 4,697

    • Multiply by the 800 foot length: 628 cubic feet.
    • Then times 7.48 for gallons.
    • That is about 4,697 gallons.

    Quick trick: Estimate: 628 × 7.5 is about 4,710. The real answer is right there.

Remember this for good

A 12 inch main is exactly 1 foot across, which makes the circle simple: 0.785 times 1 times 1 is just 0.785.

12 inches is 1 foot, so the circle end is just 0.785 square feet. Then it is length times 7.48 like any pipe.

Solve it fast next time

  • 12 inches is 1 foot, so the circle end is 0.785 square feet.
  • Pipe gallons = circle times length times 7.48.
  • A 1-foot pipe is the easiest case; the circle is just 0.785.

The answer: About 4,697 gallons.

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