Water · Worked step by step

How many pounds of chlorine to disinfect a 12,000 gallon main?

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The problem

A new water main holds 12,000 gallons. To disinfect it, you want a chlorine dose of 50 mg/L. How many pounds of chlorine do you need?

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3 steps

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The written version, step by step

  1. 1

    Change gallons to million gallons

    12,000 gal = 0.012 MG

    • The pounds formula uses million gallons.
    • 12,000 divided by 1,000,000 slides the decimal 6 places left.
    • So 12,000 gallons is 0.012 MG.

    Quick trick: Divide gallons by a million: 12,000 becomes 0.012.

  2. 2

    Use the pounds formula

    pounds = 0.012 × 50 × 8.34

    • Pounds = volume in MG times dose times 8.34.
    • Drop in 0.012 MG, the 50 mg/L dose, and 8.34.
    • This is the same pounds formula you use for a daily flow.
  3. 3

    Multiply it out

    pounds = 5.0 • pounds ≈ 5 lb

    • 0.012 times 50 is 0.6.
    • 0.6 times 8.34 is 5.004.
    • So you need about 5 pounds of chlorine.

    Quick trick: 0.6 × 8.34 is about 5. Quick sanity check.

Remember this for good

Pounds of chlorine = volume in million gallons (MG) times dose (mg/L) times 8.34. Change the gallons to MG first.

It is the same pounds formula as daily flow. A new main is a one-time fill, so the volume in MG plays the part of the flow.

Solve it fast next time

  • Change gallons to MG by dividing by 1,000,000 (slide the decimal 6 places left).
  • Then pounds = MG times dose times 8.34.
  • New mains are disinfected at a high dose, often around 50 mg/L, then flushed and cleared before use.

The answer: About 5 pounds.

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