Wastewater · Worked step by step

What percent of the TSS was removed, 240 to 60?

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The problem

Wastewater comes in with TSS of 240 mg/L and leaves with 60 mg/L. What percent of the TSS was removed?

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2 steps

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The written version, step by step

  1. 1

    Find how much was removed

    removed = 240 - 60 • removed = 180 mg/L

    • In at 240, out at 60.
    • The difference is what got removed.
    • 240 - 60 = 180 mg/L.

    Quick trick: Removed is always in minus out. Subtract first.

  2. 2

    Divide by the start, make a percent

    180 ÷ 240 = 0.75 • 0.75 × 100 = 75%

    • Divide removed by the starting amount: 180 ÷ 240 = 0.75.
    • Times 100 to make it a percent.
    • So 75% of the TSS was removed.

    Quick trick: 180 ÷ 240 is the same as 3 ÷ 4 = 0.75. Simplify before dividing.

Remember this for good

Percent removed = (amount taken out divided by amount you started with) times 100.

Removed over started, times 100. You took out 180 of the original 240; 180 of 240 is three quarters, which is 75%.

Solve it fast next time

  • Subtract first to find how much was removed, then divide by the starting (in) number.
  • Always divide by the IN value, never the leftover.
  • Times 100 at the end for a percent.

The answer: 75% removed.

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